A platinum wire has a resistance of 10 - at 0-C and 20 - at 273-C- Find the value of temperature coefficient of platinum-

Temperature coefficient of resistance of platinum is $4 \times 10^{- 3} K^{- 1}$ at $0^{\circ}$ C. The temperature at which the increase in the resistance of platinum wire is 10% of its value at $0^{\circ}$ C.

Q. The temperature coefficient of resistance of platinum is

α = 3.92 \times 10^{- 1} K^{- 1}

20^{o} C

. Find the temperature at which the increase in the resistance of platinum wire is

10

of its value at

20^{o} C

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A platinum wire has a resistance of 10Ω at 0∘C and 20Ω at 273∘C. Find the value of temperature coefficient of platinum.

The correct option is A 1∘273C−1Ro=10 Ω Rt=20 Ω t=273∘C Ro=Rt(1+αt) α=Rt−RoRot α=20−1010×273=1273∘C−1

A platinum wire has a resistance of $10 Ω$ at $0^{\circ} C$ and $20 Ω$ at $273^{\circ} C$ . Find the value of temperature coefficient of platinum.

The correct option is A $\frac{1^{\circ}}{273} C^{- 1}$
$R_{o} = 10 Ω$
$R_{t} = 20 Ω$
$t = 273^{\circ} C$
$R_{o} = R_{t} (1 + α t)$
$α = \frac{R_{t} - R_{o}}{R_{o} t}$
$α = \frac{20 - 10}{10 \times 273} = {\frac{1}{273}}^{\circ} C^{- 1}$