Question

A play ground has the shape of a rectangle, with two semi-circles on its smaller sides as diameters, added its outside. If the sides of the rectangle are $36$ m and $24.5$ m, find the area of the playground. (Take $\pi$ $=\frac{27}{7}$).

Answer 1

Given $l=36m,b=24.5m$

$\Rightarrow$ Area of a rectangle $=l\times b=36\times 24.5=882m^2$

$\Rightarrow$ Radius of a semi circle $=\frac{24.5}{2}=12.25m$

$\Rightarrow$ Area of a semicircle $=\frac{\pi r^2}{2}=\frac{22\times (12.25{)}^2}{7\times 2}=235.812m^2$

$\Rightarrow$ Area of two semi-circle $=2\times 235.812=471.624m^2$

$\therefore$ Area of playground = Area of rectangle + Area of two semi-circle

$\therefore$ Area of the playground $=(882+471.624)m^2=1353.624m^2$