A player kicks a football of mass 0.75 kg, which begins to move with a velocity of 12 m/s. If the contact between the leg and the football lasts for 0.02 s, then find the force applied on the football.

2500 N

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1250 N

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450 N

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250 N

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Solution

The correct option is C 450 N
The initial momentum is given as mass times the initial velocity.

Since the football is at rest initially, the initial velocity is zero.

⇒ p $_{i}$ = m x v $_{i}$ = 0.75 x 0 = 0 kg m/s

The final momentum of the football,

p $_{f}$ = m x v $_{f}$ = 0.75 x 12 = 9 kg m/s

From Newton’s second law, the force applied is equal to the rate of change of momentum.

F = $\frac{p_{f} - p_{i}}{t}$
F = $\frac{9 - 0}{0.02}$

⇒ F = 450 N

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