Question

A player throws a ball at an angle of ${30}^o$ up with the horizontal with a velocity of $14m/s$. If the point of projection is at a height of $12m$ from the ground, then calculate the distance up to which the ball is thrown by the player. ($g=10m/s^2$)

Answer 1

It will follow parabolic path

Range is given as,

$R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{{14}^2\times \sin 60}{9.8}$

$R=17.32m$

Time taken to reach the ground in next part

$=\sqrt{\frac{2H}{g}}$

$=\sqrt{\frac{2\times 12}{9.8}}$

$=1.56sec$

Distance traveled in next part

$S=ut$

$S=14\times 1.56$

$S=21.84m$

Total distance$=21.84+17.32=39.16m$