Question

A player throws a ball in vertical upwards direction. The direction of acceleration at the highest point is ___________ and magnitude is ___________.

• A. vertically downwards
• B. $9.81m{s}^{-2}$

Answer 1

Explanation:

1. Acceleration:

• Acceleration can be defined as the rate of change of velocity with respect to time.
• It is a vector quantity.
• SI unit of acceleration is $\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right.$.

2. Direction and magnitude of acceleration at the highest point:

• If a ball is thrown vertically upwards, then the acceleration due to gravity acts on it.
• Its direction is always vertically downwards.
• When the ball reaches the highest point, at that instant its velocity is zero, and only the acceleration due to gravity acts on it.
• The value of gravity of the earth, $g=9.81m{s}^{-2}$.

Thus, The direction of acceleration at the highest point is vertically downwards and the magnitude is $\mathbf{9}\mathbf{.}\mathbf{81}\mathbf{}\mathit{m}{\mathit{s}}^{\mathbf{-}\mathbf{2}}$.