A player throws a ball upwards with an initial speed of $29.4 m s^{- 1}$ . The height to which the ball rises and the time taken to reach the player's hands are

22.05 m, 38 s

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44.1 m, 6 s

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29.4 m, 6 s

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54.5 m, 9 s

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Solution

The correct option is A $44.1 m, 6 s$
Maximum height $h = \frac{u^{2}}{g} = \frac{{(29.4)}^{2}}{2 (9.8)} = 44.1 m$
Time taken $t = 2 \sqrt{\frac{2 h}{g}} = 2 \sqrt{\frac{2 (44.1)}{9.8}} = 6 s$

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A player throws a ball upwards with an initial speed of 29.4 ms−1. The height to which the ball rises and the time taken to reach the player's hands are

The correct option is A 44.1 m,6 sMaximum height h=u2g=(29.4)22(9.8)=44.1mTime taken t=2√2hg=2√2(44.1)9.8=6s

A player throws a ball upwards with an initial speed of $29.4 m s^{- 1}$ . The height to which the ball rises and the time taken to reach the player's hands are

The correct option is A $44.1 m, 6 s$
Maximum height $h = \frac{u^{2}}{g} = \frac{{(29.4)}^{2}}{2 (9.8)} = 44.1 m$
Time taken $t = 2 \sqrt{\frac{2 h}{g}} = 2 \sqrt{\frac{2 (44.1)}{9.8}} = 6 s$