A player throws a ball upwards with an initial speed of 30 m $s^{- 1}$ . How long does the ball take to return to the player's hands? (Take g = 10 m $s^{- 2}$ ).

3 s

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6 s

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9 s

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12 s

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Solution

The correct option is D 6 s
Taking upword direction as $+ v e,$
$u = + 30 m / s a = - g m / s^{2} s = 0 [As the ball is reaching its initial position.]$
By second equation of motion,
$0 = 30 \times t + \frac{1}{2} (- 10) \times t^{2}$
$⟹ 0 = 30 - 5 t$
$⟹ t = 6 s e c$

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A player throws a ball upwards with an initial speed of 30 m s−1. How long does the ball take to return to the player's hands? (Take g = 10 m s−2).

The correct option is D 6 sTaking upword direction as +ve,u=+30m/sa=−g m/s2s=0[As the ball is reaching its initial position.]By second equation of motion, 0=30×t+12(−10)×t2⟹0=30−5t⟹t=6sec

A player throws a ball upwards with an initial speed of 30 m $s^{- 1}$ . How long does the ball take to return to the player's hands? (Take g = 10 m $s^{- 2}$ ).

The correct option is D 6 s
Taking upword direction as $+ v e,$
$u = + 30 m / s a = - g m / s^{2} s = 0 [As the ball is reaching its initial position.]$
By second equation of motion,
$0 = 30 \times t + \frac{1}{2} (- 10) \times t^{2}$
$⟹ 0 = 30 - 5 t$
$⟹ t = 6 s e c$