A playground has the shape of a rectangle,with two semi-circles on its smaller sides as diameters,added to its outside.If the sides of the rectangle are 36 m and 24.5 m,find the area of the playground. $T a k e π = \frac{22}{7}$

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Solution

Length of rectangular portion (l) = 36 m and breadth (b)=24.5 m

$∴ A r e a = l \times b = 36 \times 24.5 m^{2} = 882 m^{2}$

Radius of each semicircle (r) = $\frac{24.5}{2} = 12.25 m$

$∴ A r e a o f t w o s e m i c i r c l e s = 2 \times \frac{1}{2} π r^{2} = \frac{22}{7} \times (12.25)^{2} m^{2}$

$= \frac{22}{7} \times 150.0625 m^{2} = 471.625 m^{2}$

$∴ T o t a l a r e a o f t h e p l a y g r o u n d = 471.625 + 882 m^{2} = 1353.625 m^{2}$

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A playground has the shape of a rectangle,with two semi-circles on its smaller sides as diameters,added to its outside.If the sides of the rectangle are 36 m and 24.5 m,find the area of the playground.Take π=227

Length of rectangular portion (l) = 36 m and breadth (b)=24.5 m ∴ Area=l×b=36×24.5 m2=882 m2 Radius of each semicircle (r) =24.52=12.25 m ∴ Area of two semicircles=2×12πr2=227×(12.25)2 m2 =227×150.0625 m2=471.625 m2 ∴ Total area of the playground=471.625+882 m2=1353.625 m2

A playground has the shape of a rectangle,with two semi-circles on its smaller sides as diameters,added to its outside.If the sides of the rectangle are 36 m and 24.5 m,find the area of the playground. $T a k e π = \frac{22}{7}$