Question

A plot of log $\frac{x}{m}$ versus log P for the adsorption of a gas on a solid gives a straight line with slope equal to:

• A. n
• B. $\frac{1}{n}$
  
• C. log K
• D. - log K

Answer 1

The correct option is B $\frac{1}{n}$


If we take our original equation,
$\frac{x}{m}=k.P^{\frac{1}{n}}$
Applying log on both sides, we get
$log\left(\frac{x}{m}\right)=log(k.P^{\frac{1}{n}})$
$log\left(\frac{x}{m}\right)=logk+\frac{1}{n}logP$
If we compare this to a straight line equation, y = mx + c
You can see that y is log $\left(\frac{x}{m}\right)$,
$mxis\frac{1}{n}logP$
c is log K
So the answer is $\frac{1}{n}$