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Question

A plot of log(ax) against time 't' is a straight line. This indicates that the reaction is of:

A
zero order
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B
first order
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C
second order
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D
third order
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Solution

The correct option is B first order

Rate=d[A]dt=k[A] {By differential form of rate law}

d[A][A]=kdt

ln[A]ln[A]o=kt {By integrating both sides}

ln[A]=kt+ln[A]o


log[A]=log(ax)=kt2.303+loga

Above expression is for a straight line with slope equal to k2.303.

So the reaction is of the first order.


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