Question

A plot of $log\left(\frac{x}{m}\right)$ versus $\log P$ for the adsorption of a gas on a solid gives a straight line with slope equal to:

• A. $-\log K$
• B. $n$
• C. $\frac{1}{n}$
• D. $\log K$

Answer 1

The correct option is C $\frac{1}{n}$

The empirical relation $\frac{x}{m}=K{P}^{1/n}$ put forward by Freundlich is known as Freundlich adsorption isotherm.

Taking log on both sides it gives:

$log\frac{x}{m}=logK$ + $\frac{1}{n}logP$

Hence, option C is correct.