A plot of $P v s T$ for a given mass of gas of constant volume is a straight line. $P v s T$ at constant volumes $V_{1}$ and $V_{2}$ for an ideal gas are shown below:
Which of the following is correct?

V_{1} > V_{2}

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V_{1} < V_{2}

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V_{1} = V_{2}

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V_{1} = 2 V_{2}

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Solution

The correct option is C $V_{1} < V_{2}$
An ideal gas is a theoretical gas that has many randomly moving point particles. They do not interact, but exceptionally when they collide elastically. The ideal gas law is the equation of state of the ideal gases.

It is clear that slope at $V_{1}$ is more than at $V_{2}$ . So the growth of the plot between P and T, at $V_{1}$ volume is higher. Since for ideal gas P is inversely proportional to volume V. Thus, volume $V_{1}$ will be less than volume $V_{2}$ .

So, $V_{1} < V_{2}$

Option B is correct.

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A plot of P vs T for a given mass of gas of constant volume is a straight line. P vs T at constant volumes V1 and V2 for an ideal gas are shown below:Which of the following is correct?

A plot of $P v s T$ for a given mass of gas of constant volume is a straight line. $P v s T$ at constant volumes $V_{1}$ and $V_{2}$ for an ideal gas are shown below:
Which of the following is correct?