A plot of volume V versus temperature T for a gas at constant pressure is a straight line passing through the origin- The plots at different values of Which of the following order of pressure is correct for this gas-a p 1- p 2- p 3- p 4b p 1- p 2- p 3- p 4c p 1- p 2- p 3- p 4d p 1- p 2- p 3- p 4

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Standard XII

Chemistry

Boyle's Law

A plot of vol...

Question

A plot of volume (V) versus temperature (T) for a gas at constant pressure is a straight line passing through the origin. The plots at different values of pressure are shown in figure. Which of the following order of pressure is correct for this gas?

(a) $p_{1} > p_{2} > p_{3} > p_{4}$ (b) $p_{1} = p_{2} = p_{3} = p_{4}$

(c) $p_{1} < p_{2} < p_{3} < p_{4}$ (d) $p_{1} < p_{2} = p_{3} < p_{4}$

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Solution

Answer: (c) $p_{1} < p_{2} < p_{3} < p_{4}$

At a particular temperature, pV=constant

$T h u s p_{1} V_{1} = p_{2} V_{2} = p_{3} V_{3} = p_{4} V_{4} A s V_{1} > V_{2} > V_{3} > V_{4} T h e r e f o r e, p_{1} < p_{2} < p_{3} < p_{4}$

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Answer: (c) p1<p2<p3<p4 At a particular temperature, pV=constant Thus p1V1=p2V2=p3V3=p4V4As V1>V2>V3>V4Therefore, p1<p2<p3<p4

Answer: (c) $p_{1} < p_{2} < p_{3} < p_{4}$

At a particular temperature, pV=constant

$T h u s p_{1} V_{1} = p_{2} V_{2} = p_{3} V_{3} = p_{4} V_{4} A s V_{1} > V_{2} > V_{3} > V_{4} T h e r e f o r e, p_{1} < p_{2} < p_{3} < p_{4}$