A plumb bob is hanging from the ceiling of car. If the car move with acceleration a, the angle made by the string with the vertical is

{tan}^{- 1} (\frac{a}{g})

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{tan}^{- 1} (\frac{g}{a})

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{cos}^{- 1} (\frac{a}{g})

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{cos}^{- 1} (\frac{g}{a})

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Solution

The correct option is D ${tan}^{- 1} (\frac{a}{g})$
When car moves towards right with acceleration a then due to pseudo force the bob will tilt in backward direction making an angle $θ$ with vertical.
$tan θ = \frac{a}{g}$
$∴ θ = {tan}^{- 1} (\frac{a}{g})$

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A plumb bob is hanging from the ceiling of car. If the car move with acceleration a, the angle made by the string with the vertical is

The correct option is D tan−1(ag)When car moves towards right with acceleration a then due to pseudo force the bob will tilt in backward direction making an angle θ with vertical.tanθ=ag∴θ=tan−1(ag)

The correct option is D ${tan}^{- 1} (\frac{a}{g})$
When car moves towards right with acceleration a then due to pseudo force the bob will tilt in backward direction making an angle $θ$ with vertical.
$tan θ = \frac{a}{g}$
$∴ θ = {tan}^{- 1} (\frac{a}{g})$