Question

A plumb line suspended from the roof of a carriage moving with acceleration 'a' inclines at an angle $\theta$ with the vertical, then

• A. $a=gtan\theta$
• B. $a=F/m$
• C. $a=dV/dt$
• D. $a=d^{2}x/d{t}^2$

Answer 1

The correct option is A $a=gtan\theta$

Go in frame of carries$,$

$tan\theta =\frac{ma}{mg}$

$a=g\tan \theta$

Hence,

option $\left(A\right)$ is correct answer.