A PMMC voltmeter is connected across a series combination of a DC voltage source V1=2V and AC voltage source V2(t)=3sin(4t)V. The meter reads
A
2 V
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B
5 V
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C
(2+√3/2)V
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D
√17/2)V
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Solution
The correct option is A 2 V Total voltage across PMMC =VT=V1+V2 =2+3sin(4t)V
PMMC reads average value
Average value of V1=2V
Average value of V2=0
Average value of VT=2V
So PMMC reads =2V