A pn photo diode is fabricated from a semiconductor with a band gap of 2.5 eV. It can detect a signal of wavelength :

496 A^{o}

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6000 A^{o}

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4000 nm

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6000 nm

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Solution

The correct option is A $496 A^{o}$
$λ_{m a x} = \frac{h c}{e V}$
$= \frac{1242 e V A^{o}}{2.5 e V} = 4960 A^{o}$

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