A Pneumatic cylinder has a bore of 200 mm and a piston rod diameter of 140 mm. For an extend speed of 5 m/min.
The retract speed is
A
0.814m/sec
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B
0.562m/sec
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C
0.614m/sec
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D
0.754m/sec
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Solution
The correct option is C0.614m/sec The same fluid flow rate used to extend the cylinder(157 Lpm) is used to retract the cylinder.The retract cylinder velocity (Vr) is given byVr=QFA−a=157Lpmπ4(0.22−0.142)=0.614m/sec