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Question

A Pneumatic cylinder has a bore of 200 mm and a piston rod diameter of 140 mm. For an extend speed of 5 m/min.

The retract speed is

A
0.814 m/sec
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B
0.562 m/sec
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C
0.614 m/sec
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D
0.754 m/sec
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Solution

The correct option is C 0.614 m/sec
The same fluid flow rate used to extend the cylinder (157 Lpm) is used to retract the cylinder. The retract cylinder velocity (Vr) is given by Vr=QFAa=157Lpmπ4(0.220.142)=0.614m/sec

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