wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A pnp transistor is used in common emitter mode in an amplifier circuit. When base current is charged by an amount ΔIB, the collector current changes by 4mA. If the current amplification factor is 60, then the value of ΔIB is:

A
240 mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
66.6 μA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
60 μA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15 μA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 66.6 μA
Current amplification factor is the change in collector current per unit change in base current.
β=ΔICΔIB

ΔIB=4 mA60=66.6 μA

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PN Junction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon