A point A is 17 cm away from the center of the circle and the length of tangent drawn from A to the circle is 15 cm. Find the radius of the circle.

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Solution

Given that AB = 15 cm, AO = 17 cm

To find BO

Applying Pythagoras theorem

${B O}^{2}$ = ${A O}^{2}$ – ${A B}^{2}$

${B O}^{2}$ = $17^{2}$ – $15^{2}$

${B O}^{2}$ = 289 – 225

${B O}^{2}$ = 64

BO = 8 cm

Therefore the radius of the circle is 8 cm

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A point A is 17 cm away from the center of the circle and the length of tangent drawn from A to the circle is 15 cm. Find the radius of the circle. __

Given that AB = 15 cm, AO = 17 cm To find BO Applying Pythagoras theorem BO2 = AO2 – AB2 BO2 = 172 – 152 BO2 = 289 – 225 BO2 = 64 BO = 8 cm Therefore the radius of the circle is 8 cm

A point A is 17 cm away from the center of the circle and the length of tangent drawn from A to the circle is 15 cm. Find the radius of the circle.

__

Given that AB = 15 cm, AO = 17 cm

To find BO

Applying Pythagoras theorem

${B O}^{2}$ = ${A O}^{2}$ – ${A B}^{2}$

${B O}^{2}$ = $17^{2}$ – $15^{2}$

${B O}^{2}$ = 289 – 225

${B O}^{2}$ = 64

BO = 8 cm

Therefore the radius of the circle is 8 cm