A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to a point on the ground which is at a certain distance from the foot of the pole. The height of the pole, if the angle made by the rope with the ground level is $30^{\circ}$ is ___ m.

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A point C on the level ground is at some distance from a 15 m pole AB. If the angle of elevation of the top of the pole from point C is 30°, then how far is point C from the foot of the pole?

The correct option is C 15√3m The situation is represented in the figure below tan30∘=ABBC⇒BC=ABtan30∘=151√3=15√3m∴Distance of point C from pole is 15√3 m

The correct option is C
$15 \sqrt{3} m$

The situation is represented in the figure below

$t a n 30^{\circ} = \frac{A B}{B C} \Rightarrow B C = \frac{A B}{t a n 30^{\circ}} = \frac{15}{\frac{1}{\sqrt{3}}} = 15 \sqrt{3} m ∴ D i s t a n c e o f p o i n t C f r o m p o l e i s 15 \sqrt{3} m$