Question

A point charge is placed at the origin O. Work done in taking another point charge -Q from the point A(0, a) to another point B(a, 0) along the straight path AB is

• A. Zero
• B. $\left(\frac{-qQ}{4\pi {\omega }_0}\frac{1}{a^2}\right)\sqrt{2}a$
• C. $\left(\frac{qQ}{4\pi {\omega }_0}\frac{1}{a^2}\right)\frac{a}{\sqrt{2}}$
• D. $\left(\frac{qQ}{4\pi {\omega }_0}\frac{1}{a^2}\right)\sqrt{2}a$

Answer 1

The correct option is A

Zero

Since A and B are at equal potential so potential difference between A and B is zero. Hence $W=q.\Delta V=0$