Question

A point charge of +12$\text{μC}$ is at a distance $6\text{cm}$ vertically above the centre of a square of side $12\text{cm}$ as shown in figure. The magnitude of the electric flux through the square will be $\times {10}^3{\text{Nm}}^2/\text{C}$

Answer 1

Using Gauss law, it is a part of cube of side $12\text{cm}$ and charge at centre, $\varphi =\frac{Q}{6{ϵ}_0}=\frac{12\mu C}{6{ϵ}_0}=226\times {10}^3{\text{Nm}}^2/\text{C}$