A point charge of 2.0 μC is at the centre of a cubic Gaussiansurface 9.0 cm on edge. What is the net electric flux through thesurface?
Given: The magnitude of the point charge is 2.0 μC and the edge length of a Gaussian surface is 9.0 cm .
Using Gauss’s theorem, the net electric flux through all six faces of cube is given as,
ϕ T = q ε 0
Where, the charge placed at the center of the cube is q and the net electric flux through all six faces of the cube is ϕ T .
The permittivity of free space is given as,
ε 0 = 8.854 × 10 − 12 C 2 / Nm 2
By substituting the given values in above equation, we get
ϕ = 2 × 10 − 6 8.854 × 10 − 12 = 2.26 × 10 5 Nm 2 / C
Thus, the magnitude of the net electric flux through the square is 2.26 × 10 5 Nm 2 / C .
Given: The magnitude of the point charge is
Using Gauss’s theorem, the net electric flux through all six faces of cube is given as,
Where, the charge placed at the center of the cube is
The permittivity of free space is given as,
By substituting the given values in above equation, we get
Thus, the magnitude of the net electric flux through the square is
