A point charge of $40 s t a t$ coulomb is placed $2 c m$ in front of an earthed metallic plane plate of large size. Then, the force of attraction on the point charge is

100 d y n e s

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160 d y n e s

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1600 d y n e s

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400 d y n e s

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Solution

The correct option is D $400 d y n e s$
R.E.F image
induced change on the
metallic plate $= - 40$ state
$\Rightarrow$ attraction $= \frac{1}{4 π w} \times \frac{| q_{1} q_{2} |}{r^{2}}$
$F = 1 \times \frac{40 \times 40}{(2)^{2}}$
$F = 400 d y m e s$

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A point charge of 40 stat coulomb is placed 2 cm in front of an earthed metallic plane plate of large size. Then, the force of attraction on the point charge is

The correct option is D 400 dynesR.E.F imageinduced change on themetallic plate =−40 state⇒ attraction =14πw×|q1q2|r2F=1×40×40(2)2F=400dymes

A point charge of $40 s t a t$ coulomb is placed $2 c m$ in front of an earthed metallic plane plate of large size. Then, the force of attraction on the point charge is

The correct option is D $400 d y n e s$
R.E.F image
induced change on the
metallic plate $= - 40$ state
$\Rightarrow$ attraction $= \frac{1}{4 π w} \times \frac{| q_{1} q_{2} |}{r^{2}}$
$F = 1 \times \frac{40 \times 40}{(2)^{2}}$
$F = 400 d y m e s$