Question

A point charge of $5\times {10}^{-6}$C experiences a force of $2\times {10}^{-3}$N when kept in a uniform electric field of intensity E. Find E.

Answer 1

Given: $q=5\times {10}^{-6}$C
$F=2\times {10}^{-3}$N
We know that, Electric field intensity$=E=\frac{F}{q}$ $=\frac{2\times {10}^{-3}}{5\times {10}^{-6}}=400N/C$