Question

A point charge of charge Q moving with angular velocity $\omega$ in circle of radius R find $\overrightarrow{B}$ at centre.

Answer 1

Given angular velocity =$\omega$ and radius =$R$

We know linear velocity of the point charge particle ,$V=\omega R$----(A)

Also we know magnetic field $\overrightarrow{B}=\frac{{\mu }_0}{4\pi }\frac{QVR}{R^3}$

Reducing the value of A in the above mentioned equation we get,

$\overrightarrow{B}=\frac{{\mu }_0}{4\pi }\frac{Q\omega R^2}{R^3}$

$\overrightarrow{B}=\frac{{\mu }_0}{4\pi }\frac{Q\omega }{R}$