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Question

A point charge Q is located at the center of the hollow spherical conductor of inner radius R1 and outer radius R2 , the conductor being uncharged initially. The potential at the inner surface will be

A
KQ[1R1+1R2]
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B
KQ[1R11R2]
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C
KQ[1R21R1]
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D
None of these
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Solution

The correct option is A KQ[1R1+1R2]
Given that,
Inner radius=R
Outer radius=R2
Now, Potential dueto R1=KQR1
Potential due to R2=KQR2
Total potential =KQR1+kQR2
Potential=KQ[1R1+1R2]


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