A point charge Q is located just above the centre O of the flat face of a hemisphere as shown in the figure. The electric flux through the flat face is
A
Q2ϵ0
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B
−Q2ϵ0
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C
Qϵ0
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D
−Qϵ0
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Solution
The correct option is B−Q2ϵ0 The enclose the charge Q, we can assume another hemisphere kept above the given hemisphere as shown in the figure.
Now, by Gauss's law, electric flux through the closed surface will be,
ϕ=qenclosedϵo=Qϵ0
Further through given flat face of hemisphere, electric flux will be,
ϕ=−Q2ϵo [By symmetry]
Here negative sign arises because the positive normal to the flat face is outwards (along +y - axis) and electric field through O is along −y - axis.