A point charge q is placed at the vertex of cone of semivertical angle 37o as shown in figure. Flux associated with half cone ABCO is nqϵo then n is (Write upto two digits after the decimal point.)
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Solution
θ=37o So the solid angle Ω is given by, Ω=2π(1−cos37o)=2π(1−45)=2π5 ϕnet=qϵo⇒ϕ=ϕnet4π.Ω=q4πϵo.2π5=q10ϵo