A point charge +q is placed on the axis of a ring of radius R at distance r from the centre ,then electric flux through the ring due to the point charge will be

Open in App

Solution

Suggest Corrections

Similar questions

A ring of radius R is charged uniformly with a charge +Q. The electric field at a point on its axis at a distance r from any point on the ring will be:-

Q. A ring of radius

R

is charged uniformly with a charge

+ Q

. The electric field at any point on its axis at a distance

r

from the circumference of the ring will be

Q. A point charge

Q

is located at centre of a fixed thin ring of radius

R

with uniformly distributed charge

- Q

. The magnitude of the electric field strength at the point lying on the axis of the ring at a distance

x

from the centre is

(x >> R)

Q. A point charge 'q' is placed at a distance 'l' from the centre of a disc of radius 'R' along its axis. The electric flux through the disc is

Q. A point charge

q

is located at the centre of a thin ring of radius

R

with uniformly distributed charge

- q

. Find the magnitude of the electric field strength vector at the point lying on the axis of the ring at a distance

x

from its centre, if

x >> R

Join BYJU'S Learning Program