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Question

A point charge q moves from A to B along a parabolic path (AB is latus rectum). Electric field is along x−axis. The work done by the field is
1016485_8a6c0205825c4171b77467a99414d6d5.PNG

A
qEa
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B
+qEa
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C
2qEa
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D
4qEa
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Solution

The correct option is D 4qEa

At latus rectum.

The equation of the parabola is y2=4ax

Therefore, The focal length =a

Therefore, the length of the latus ractum =4a

As the particle is moving along the latus rectum,

Total displacement in the direction of electric field, d=4a

Work done by electric field, w=qE.d=qE.4a=+4qEa

Hence, work done in electric field is +4qEa


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