Question

A point charged particle of mass $2\times {10}^{-4}kg$ is moving perpendicular to the uniform magnetic field of magnitude 0.1-tesla.Calculate the acceleration of the particle due to the magnetic field if its velocity is $3\times {10}^{4}m/s$ and its charge is $+4.0\times {10}^{-9}C$.

• A. 0.0006 $m/s^2$
• B. 0.006 $m/s^2$
• C. 0.06 $m/s^2$
• D. 0.6 $m/s^2$
• E. None of the above

Answer 1

The correct option is C 0.06 $m/s^2$

If a be the acceleration of the particle due to only magnetic field B , then

$ma=qvB$

or $a=\frac{qvB}{m}$
$=\frac{(4\times {10}^{-9})\times (3\times {10}^4)\times 0.1}{2\times {10}^{-4}}$
$=0.06m/s^2$