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Position of a Point with Respect to Circle

A point equid...

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A point equidistant from the line 4x + 3y +10 = 0, 5x - 12y + 26 = 0 and 7x + 24y - 50 = 0 is ?

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Q. A point equidistant from the line 4x + 3y + 10 = 0, 5x − 12y + 26 = 0 and 7x+ 24y − 50 = 0 is

(a) (1, −1)
(b) (1, 1)
(c) (0, 0)
(d) (0, 1)

Q. Find the equation. of the straight line equidistant from the straight lines 4x +3y+10=0 and 4x +3y+2=0.

Q. For the straight lines

4 x + 3 y - 6 = 0

5 x + 12 y + 9 = 0

the equation of the bisector of the acute angle between between them =

7 x + 9 y - 3 = 0

Q. Assertion :Each point on the line

y - x + 12 = 0

is equidistant from the lines

4 y + 3 x - 12 = 0

3 y + 4 x - 24 = 0

Reason: The locus of a point which is equidistant from two given lines is the angular bisector of the two lines.

Q. For the straight lines

4 x + 3 y - 6 = 0

5 x + 12 y + 9 = 0

, find the Bisector of the angle which contains

(0, 0)

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