A point inside the circle $x^{2} + y^{2} + 3 x - 3 y + 2 = 0$ is

(-1, 3)

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(-2, 1)

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(2, 1)

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(-3, 2)

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Solution

The correct option is B (-2, 1)
Point is inside, outside or on the circle as $S_{1}$ is <, >, = 0. For point (– 2, 1), $S_{1}$ < 0.

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(- 1, 2)

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