A point light source is kept in front of a convex mirror at a distance of 40 cm. The focul length of the mirror is 40 cm. Find the position of image.

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Solution

f = 40 cm

u = -40 cm

so,
$1 over v equals 1 over 40 minus fraction numerator negative 1 over denominator 40 end fraction 1 over v equals 2 over 40$
thus,

v = 20cm

so, the image will be formed behind the mirror and thus will be virtual.

here's the ray diagram

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A point light source is kept in front of a convex mirror at a distance of 40 cm. The focul length of the mirror is 40 cm. Find the position of image.

f = 40 cm u = -40 cm so, thus, v = 20cm so, the image will be formed behind the mirror and thus will be virtual. here's the ray diagram

f = 40 cm

u = -40 cm

so,
$1 over v equals 1 over 40 minus fraction numerator negative 1 over denominator 40 end fraction 1 over v equals 2 over 40$
thus,

v = 20cm

so, the image will be formed behind the mirror and thus will be virtual.

here's the ray diagram