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Question

A point mass m moving with velocity v0 hits a ball of same mass m at rest elastically. After the collision, point mass moves with velocity v0/2 at an angle θ from initial direction of motion. Then value of θ is

A
300
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B
450
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C
600
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D
900
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Solution

The correct option is C 600

Let v=Velocity of ball
Applying conservation of linear momentum in the direction of motion,
mv0=m.v02cosθ+m.vcosα ...(1)....Applying conservation of linear momentum in the direction perpendicular to the direction of motion,
mVo2sin(θ)=mVsin(α) ....(2)
Applying conservation of kinetic energy,
12mV2o=12m(Vo2)2+12mV234V2o=V2V=32V .....(3)

solving (1), (2) and (3), we get
θ=600

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