A point moves such that sum of square of its distances from x− axis and y−axis is equal to square of its distance from z−axis, then the locus of point is
A
X−axis
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B
Z−axis
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C
XY− plane
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D
YZ−plane
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Solution
The correct option is CXY− plane Let point is P(x,y,z) , then
Distance from x−axis =√y2+z2,
Distance from y−axis =√x2+z2,
Distance from z−axis =√y2+x2
According to statement, (y2+z2)+(x2+z2)=y2+x2⇒z2=0∴z=0 i.e.XY− plane