CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A point moves with uniform acceleration and v1,v2 and v3 denote the average velocities in the three successive intervals of time t1,t2 and t3 Which of the following relations is correct

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

Let u1,u2,u3 and u4 be velocities at time t = 0,t1,(t1+t2) and (t1+t2+t3) respectively and acceleration is α then,

v1 = u1 + u22,v2 = u2 + u32 and v3 = u3 + u42

Also, u2=u1+at1,u3=u1+a(t1+t2)

and u4 = u1 + a(t1 + t2 + t3)

By solving, we get v1v2v2v3 = (t1+t2)(t2+t3)


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon