A point object is placed at 12 cm from converging lens of 15 cm focal length- then which statement is true for image-A- Image is 6 times magnifiedB- Image is virtual and at 50 cm from lensC- Image is virtual and at 60 cm from lensD- Image is real and at 60 cm from lens

The correct option is C Image is virtual and at 60 cm from lensu = 12 cm f = +15 cm 1/v 1/u = 1/f 1/v + 1/12 = 1/15 1/v = 1/15 1/12 = 4/60 5/60 v = 60 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Image in Thin Lens Using Formula

A point objec...

Question

A point object is placed at 12 cm from converging lens of 15 cm focal length, then which statement is true for image?

Image is 6 times magnified

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Image is virtual and at 50 cm from lens

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Image is virtual and at 60 cm from lens

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Image is real and at 60 cm from lens

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Image is virtual and at 60 cm from lens
$u$ = -12 cm
$f$ = +15 cm
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} + \frac{1}{12} = \frac{1}{15}$
$\frac{1}{v} = \frac{1}{15} - \frac{1}{12} = \frac{4}{60} - \frac{5}{60}$
$v$ = -60 cm

Suggest Corrections

Similar questions

Q. A 5 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find the position and nature of the image formed.

Q. Find the position and nature of the image formed by the concave mirror of focal length

20 cm

, if the object

O

is placed at a distance

30 cm

from the pole.

Q. Flat surface of a plano-convex lens of focal length 20 cm is silvered. If object is placed at 60 cm from lens then distance of image from lens is

Q. A point object is placed at

15 cm

in front of a convex lens of focal length

10 cm

. Where shall we place a convex mirror of focal length

13 cm

so that real image and object coincide?

Q. An object is placed 50 cm from a lens which produces a virtual image at a distance of 10 cm in front of the lens. Calculate the focal length of the lens.

Join BYJU'S Learning Program

A point object is placed at 12 cm from converging lens of 15 cm focal length, then which statement is true for image?

The correct option is C Image is virtual and at 60 cm from lensu = -12 cm f = +15 cm 1v−1u=1f 1v+112=115 1v=115−112=460−560 v = -60 cm

The correct option is C Image is virtual and at 60 cm from lens
$u$ = -12 cm
$f$ = +15 cm
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} + \frac{1}{12} = \frac{1}{15}$
$\frac{1}{v} = \frac{1}{15} - \frac{1}{12} = \frac{4}{60} - \frac{5}{60}$
$v$ = -60 cm