Question

A point object of mass M is projected with a speed $10m{s}^{-1}$ at an angle ${60}^o$ with the horizontal. The speed at the highest point of its trajectory is.

• A. $5m{s}^{-1}$
• B. $Zero$
• C. $10m{s}^{-1}$
• D. $5\sqrt{3}m{s}^{-1}$
• E. $10\sqrt{3}m{s}^{-1}$

Answer 1

The correct option is A $5m{s}^{-1}$

At highest point of its trajectory , the speed of the object $\left(v\right)=$ Horizontal component of velocity $=V\cos \theta$

$\Rightarrow v=10\times cos{60}^0=5m/s$

Therefore, A is correct option.