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Question

A point on the ellipse x2+3y2=37 where the normal is parallel to the line 6x−5y=2 is

A
(5,2)
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B
(5,2)
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C
(5,2)
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D
(5,2)
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Solution

The correct options are
B (5,2)
D (5,2)
Differentiating the equation of ellipse,
x2+3y2=37, w.r.t. x,
dydx=x3y
Slope of the normal
mn=dxdy=3yx
Slope of the given line is,
3yx=652x=5y

Hence, the points in options (b) and (d) are satisfying the above relation.

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