A point P has coordinates (7,10) in a coordinate system X′OX↔Y′OY. Suppose it has coordinates (10,7) in another coordinate system X′1O1X1↔Y′1O1Y1 with X′OX↔X′1O1X1. Find the coordinates of O1 in the system X′OX↔Y′OY.
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Solution
P has coordinates (7,10) in a coordinate system X′OX↔Y′OY.
Also, it has coordinates (10,7) in a coordinate system X′1O1X1↔Y′1O1Y1.
So, X′1O1X1 intersect X′OX at the point 7−10=−3 and Y′1O1Y1 intersect Y′OY at the point 10−7=3
Thus, X′1O1X1 and Y′1O1Y1 intersect each other at the point (−3,3) in coordinate system X′OX↔Y′OY and O1 has coordinates (−3,3).
Hence, coordinates of O1 in th system X′OX↔Y′OY is (−3,3).