A point P is 13 cm from the centre of the circle. The length of the tangent drawn from P to the circle is 12cm. Find the radius of the circle.
The angle subtended by AB at P and Q are either equal or supplementary.
Since,
tangent to a circle is perpendicular to the radius through the point of contact
So, ∠OTP=900
So, in triangle OTP
(OP)2=(OT)2+(PT)2
132=(OT)2+122
(OT)2=132−122
OT2=25
OT=√25
OT=5
So, radius of the circle is 5 cm