A point P is 25cm from the centre of a circle. The radius of the circle is 7cm and length of the tangent drawn from P to the circle is x cm. The value of x= is
Given- O is the
centre of a circle to which a tangent PT=x has been drawn to the circle at T
when OP=25cm. The radius of the given circle=7cm
To find out: x=?
Solution- We join OT.
∴OT is a radius of the circle through the point of contact T
of the tangent PT. We know that the radius through the point of contact of
a tangent to a circle is perpendicular to the tangent.
∴OT⊥PT⟹∠OTP=90o.
∴ΔOTP is a right one
with OP as hypotenuse. So, applying Pythagoras theorem, we get
PT=√OP2−OT2=√252−72cm=24cm.
∴ The tangent to the given circle PT=24cm.
Ans- Option-B.