A point P is $26 c m$ away from the centre O of a circle and the length PT of tangent drawn from P to the circle is $10 c m$ . Then the radius of the circle is

18 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $24 c m$
A tangent forms a right angled triangle when it touches the circle, with the radius of the circle and the length of the tangent as sides and distance of the point from the radius is the hypotenuse.
Hence, $r^{2} + 10^{2} = 26^{2}$
$\Rightarrow r = 24$ cm

Suggest Corrections

Similar questions

A point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 10 cm. Find the radius of the circle.

In the given figure, point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 24 cm. Then the radius of the circle is

(a) 10 cm (b) 12 cm (c) 13 cm (d) 15 cm

Q. In the given figure, point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 24 cm. Then the radius of the circle is [CBSE 2011, 12]
(a) 10 cm
(b) 12 cm
(c) 13 cm
(d) 15 cm

Q. In a circle of radius 7 cm, tangent PT is drawn from a point P, such that PT = 24 cm. If O is the centre of the circle, then OP = ?

(a) 30 cm
(b) 28 cm
(c) 25 cm
(d) 18 cm

Q. From a point P, 10 cm away from the centre of a circle, a tangent PT of length 8 cm is drawn. Find the radius of the circle.

Join BYJU'S Learning Program

A point P is 26cm away from the centre O of a circle and the length PT of tangent drawn from P to the circle is 10cm. Then the radius of the circle is

The correct option is D 24cmA tangent forms a right angled triangle when it touches the circle, with the radius of the circle and the length of the tangent as sides and distance of the point from the radius is the hypotenuse. Hence, r2+102=262⇒r=24 cm

A point P is $26 c m$ away from the centre O of a circle and the length PT of tangent drawn from P to the circle is $10 c m$ . Then the radius of the circle is

The correct option is D $24 c m$
A tangent forms a right angled triangle when it touches the circle, with the radius of the circle and the length of the tangent as sides and distance of the point from the radius is the hypotenuse.
Hence, $r^{2} + 10^{2} = 26^{2}$
$\Rightarrow r = 24$ cm