A point $P$ is at a distance of $29$ cm from the centre of a circle of radius $20$ cm. Find the length of the tangent drawn from $P$ to the circle.

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Solution

$O P^{2} = Q P^{2} + Q O^{2}$
$(29)^{2} = Q P^{2} + (20)^{2}$
$Q P^{2} = 841 - 400$
$Q P^{2} = 441$
$Q P = 21 c m$

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A point P is at a distance of 29 cm from the centre of a circle of radius 20 cm. Find the length of the tangent drawn from P to the circle.

OP2=QP2+QO2(29)2=QP2+(20)2QP2=841−400QP2=441QP=21cm

A point $P$ is at a distance of $29$ cm from the centre of a circle of radius $20$ cm. Find the length of the tangent drawn from $P$ to the circle.

$O P^{2} = Q P^{2} + Q O^{2}$
$(29)^{2} = Q P^{2} + (20)^{2}$
$Q P^{2} = 841 - 400$
$Q P^{2} = 441$
$Q P = 21 c m$