CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A point P is the contact point of wheel on the ground which rolls on ground without slipping. Find the value of displacement of the point P when wheel completes half revolution. Radius of the wheel is 1 m.

A
2 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
π2+4 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
π m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π2+2 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B π2+4 m
When a body is under pure rolling then the moment it completes 1 revolution, the horizontal distance covered is equal to perimeter of circle i.e 2πr
given, radius of wheel is r=1 m


Initial position, P is in contact with ground
After 12 revolution it reached the highest point B on wheel.
Horizontal distance PA given by,
x=2πr2=πr=π×1
From the right angled triangle ΔPBA, applying pythagoras theorem:
PB=PA2+AB2=(π×1)2+(2×1)2
Displacement of point P ,
PB=π2+4 m

flag
Suggest Corrections
thumbs-up
25
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon