A point P lies on the axis of a flat coil carrying a current. The magnetic moment of the coil is π. The distance of P from the coil is d, which is large compared to the radius of the coil. The magnetic field at P has magnitude
A
μ02π[πd3]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
μ04π[πd3]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
μ06π[πd2]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
μ08π[πd2]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Aμ02π[πd3] The magnetic field at P due to the flat coil of n turns, radius r, carrying current i is B=μ02.nir2(d2+r2)≅μ02.nir2d3(d>>r)=μ02π,n(πr2)d3=μ02π.πd3.